Saturday, 18 October 2014

Term 4, Week 2 Maths Challenge



Leave your answer and working out in the comment box with your name. You can also comment on how others have solved the problem. 
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10 comments:

  1. Anonymous20 October 2014 at 09:15

    7+7+7+7+7+7+7+3

    George.B

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    Replies
    1. Anonymous20 October 2014 at 13:24

      Well done you had a go at answering this challenge. Look at what I posted for Zan and Archie. Mr Janse

      Delete
  2. Anonymous20 October 2014 at 09:18

    7+7+7+7+7+3+7+7
    There are seven zepts and one zio

    Olivia P

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    Replies
    1. Anonymous20 October 2014 at 13:24

      Well done you had a go at answering this challenge. Look at what I posted for Zan and Archie. Mr Janse

      Delete
  3. Anonymous20 October 2014 at 09:41

    I think there are 7 zepts and 1 zio because 7x7 is 49 and 1x3 is 3 and 49+3= 52.
    This is the only answer.

    Zan

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    Replies
    1. Anonymous20 October 2014 at 13:21

      Well done for having a go. I wonder if you checked the question again because it says there was more than one of each creature. Will your answer still be correct? Mr Janse

      Delete
  4. Anonymous20 October 2014 at 09:42

    7 x 7 = 49
    49 + 3 = 52
    so there is 7 zepts and 1 zio
    this is the only answer

    ReplyDelete
    Replies
    1. Anonymous20 October 2014 at 13:23

      Great you had a go at answering the question. I wonder if you double check the question if you would still agree. It said that there was more than one of each creature. There may also be other solutions if you give it another go. Mr Janse

      Delete
  5. Anonymous20 October 2014 at 20:40

    7 x 7 =49
    49 + 3 = 52
    so there is 7 zepts and 1 zio
    and there could be 1 zept and 15 zios
    which means there is two answers not one
    blake

    ReplyDelete
  6. Anonymous20 October 2014 at 21:06

    7 x 7 = 49
    49 + 3 = 52
    so there could be 7 zepts and 1 zio
    7 x 1 = 7
    7 + (3 x 15) = 52
    which means there could also be 1 zept and 15 zios
    4 x 7 = 28
    8 x 3 = 24
    28 + 24 = 52
    so there also could be 4 zepts and 8 zios
    Blake

    ReplyDelete

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